Discussion:
Help!!! Complex Number
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j***@orange.net
2005-11-23 09:42:19 UTC
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Having a problem with this question, can anyone help...........

given that z= a+jb and 4 + j + 3(2+j5) = 1+j4
----- --------
z 2+j2


obtain values for a and b

any help would be grate

cheers

Jim
harry
2005-11-23 09:51:33 UTC
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Post by j***@orange.net
Having a problem with this question, can anyone help...........
given that z= a+jb and 4 + j + 3(2+j5) = 1+j4
----- --------
z 2+j2
obtain values for a and b
any help would be grate
cheers
Jim
It isn't clear from what you've written which are the numerators of the two
fractions.

For example, in your second equation do you mean:
4 + j + 3(2+j5)/z = (1+j4)/(2+2j)

or maybe something else?
j***@orange.net
2005-11-23 11:46:10 UTC
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Hope this is clearer

4+j /z + 3(2+j5) / 2+j2 = 1+ j4

Jim
j***@orange.net
2005-11-23 11:50:29 UTC
Permalink
given that z= a + jb

and

4+j /z + 3(2+j5) / 2+j2 = 1+ j4

obtain values for a and b

jim
harry
2005-11-23 18:02:20 UTC
Permalink
Post by j***@orange.net
given that z= a + jb
and
4+j /z + 3(2+j5) / 2+j2 = 1+ j4
obtain values for a and b
jim
Try replacing z with a + jb in your second formula.

Multiply the formula by each of the denominators, so that all fractions are
removed.

Multiply out the brackets, remembering that j * j = -1

You will then be left with an equation with some terms involving j and some
not involving j.

You can then split this into two separate equations, one containing only the
terms without j, and the other containing only the coefficients of j.

These two equations can then be solved for a and b.

Hope that helps.

Come back if you've still got problems, showing your working.

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